\(\int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx\) [130]

Optimal result

Integrand size = 14, antiderivative size = 23 \[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \]

[Out]

Chi(1/2*x)*sech(1/2*x)*(a+a*cosh(x))^(1/2)

Rubi [A] (verified)

Time = 0.07 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3400, 3382} \[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a} \]

[In]

Int[Sqrt[a + a*Cosh[x]]/x,x]

[Out]

Sqrt[a + a*Cosh[x]]*CoshIntegral[x/2]*Sech[x/2]

Rule 3382

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[c*f*(fz/d)
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3400

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[(2*a)^IntPart[n]
*((a + b*Sin[e + f*x])^FracPart[n]/Sin[e/2 + a*(Pi/(4*b)) + f*(x/2)]^(2*FracPart[n])), Int[(c + d*x)^m*Sin[e/2
+ a*(Pi/(4*b)) + f*(x/2)]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[n
+ 1/2] && (GtQ[n, 0] || IGtQ[m, 0])

Rubi steps \begin{align*} \text {integral}& = \left (\sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh \left (\frac {x}{2}\right )}{x} \, dx \\ & = \sqrt {a+a \cosh (x)} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\sqrt {a (1+\cosh (x))} \text {Chi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \]

[In]

Integrate[Sqrt[a + a*Cosh[x]]/x,x]

[Out]

Sqrt[a*(1 + Cosh[x])]*CoshIntegral[x/2]*Sech[x/2]

Maple [F]

\[\int \frac {\sqrt {a +a \cosh \left (x \right )}}{x}d x\]

[In]

int((a+a*cosh(x))^(1/2)/x,x)

[Out]

int((a+a*cosh(x))^(1/2)/x,x)

Fricas [F(-2)]

Exception generated. \[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate((a+a*cosh(x))^(1/2)/x,x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

Sympy [F]

\[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\int \frac {\sqrt {a \left (\cosh {\left (x \right )} + 1\right )}}{x}\, dx \]

[In]

integrate((a+a*cosh(x))**(1/2)/x,x)

[Out]

Integral(sqrt(a*(cosh(x) + 1))/x, x)

Maxima [F]

\[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\int { \frac {\sqrt {a \cosh \left (x\right ) + a}}{x} \,d x } \]

[In]

integrate((a+a*cosh(x))^(1/2)/x,x, algorithm="maxima")

[Out]

integrate(sqrt(a*cosh(x) + a)/x, x)

Giac [F]

\[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\int { \frac {\sqrt {a \cosh \left (x\right ) + a}}{x} \,d x } \]

[In]

integrate((a+a*cosh(x))^(1/2)/x,x, algorithm="giac")

[Out]

integrate(sqrt(a*cosh(x) + a)/x, x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\sqrt {a+a \cosh (x)}}{x} \, dx=\int \frac {\sqrt {a+a\,\mathrm {cosh}\left (x\right )}}{x} \,d x \]

[In]

int((a + a*cosh(x))^(1/2)/x,x)

[Out]

int((a + a*cosh(x))^(1/2)/x, x)